a. log 9 . log 7 . 49 log 32
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Jawab:
Penjelasan dengan langkah-langkah:
[tex]log 9 . log 7 . ^{49} log 32 = log 3^2 . log 7. ^{7^2}log 2^5 = log 3^2 . log 7. \frac{5}{2} ^{7}log 2[/tex]
[tex]= log 3^2 . log 7. ^{7}log 2 \frac{5}{2} = ^{1^{1}} log 3^2 . log 2 \frac{5}{2}[/tex]
[tex]= 2 log 3 . log 2 \frac{5}{2} = 5 log (3.2) = 5 log 6[/tex]
ndak tau nih benar atau ndak
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